THIRD EQUATION OF MOTION:
v= Final Velocity
u = Initial Velocity
a= Acceleration
s= Distance
Let us derive the third equation of motion
Distance travelled=average velocity X time
(I)
But from the first equation of motion, v = u + at
Substituting the value of t in Eq (I)
or
Example: A car is moving with an initial velocity of 5 m/s . The final velocity is 25 m/s when it accelerates at thr rate of 6 m/sq. s. Find the distance travelled
Sol: u = 5 m/s
v= 25 m/s
a = 6 m/sq. s
s = ?
(25+5)(25-50 = 12 s
30 X 20 = 12 s
600 = 12 s
The three equations listed can be used to solve the majority of kinematic problems.
The speed of a car reduces from over a displacement of 8 m. What is the unifomr acceleration of the car ? | |||
Right Option : A | |||
View Explanation |
A body with an initial velocity of 36 km/h accelerates uniformly at the rate of 18 cm over a distance of 200 m. calculate: the acceleration in m and its final velocity in m | |||
Right Option : A | |||
View Explanation |
A body is thrown vertically upwards and rises to a height of 10 m. the velocity with which the body was thrown upwards is (g=9.8m/ | |||
Right Option : C | |||
View Explanation |
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